我玩的应用:

|
- public class LatLonUtil {
-
- private static final double PI = 3.14159265;
- private static final double EARTH_RADIUS = 6378137;
- private static final double RAD = Math.PI / 180.0;
- //@see http://snipperize.todayclose.com/snippet/php/SQL-Query-to-Find-All-Retailers-Within-a-Given-Radius-of-a-Latitude-and-Longitude--65095/
- //The circumference of the earth is 24,901 miles.
- //24,901/360 = 69.17 miles / degree
- /**
- * @param raidus 单位米
- * return minLat,minLng,maxLat,maxLng
- */
- public static double[] getAround(double lat,double lon,int raidus){
-
- Double latitude = lat;
- Double longitude = lon;
-
- Double degree = (24901*1609)/360.0;
- double raidusMile = raidus;
-
- Double dpmLat = 1/degree;
- Double radiusLat = dpmLat*raidusMile;
- Double minLat = latitude - radiusLat;
- Double maxLat = latitude + radiusLat;
-
- Double mpdLng = degree*Math.cos(latitude * (PI/180));
- Double dpmLng = 1 / mpdLng;
- Double radiusLng = dpmLng*raidusMile;
- Double minLng = longitude - radiusLng;
- Double maxLng = longitude + radiusLng;
- //System.out.println("["+minLat+","+minLng+","+maxLat+","+maxLng+"]");
- return new double[]{minLat,minLng,maxLat,maxLng};
- }
-
- /**
- * 根据两点间经纬度坐标(double值),计算两点间距离,单位为米
- * @param lng1
- * @param lat1
- * @param lng2
- * @param lat2
- * @return
- */
- public static double getDistance(double lng1, double lat1, double lng2, double lat2)
- {
- double radLat1 = lat1*RAD;
- double radLat2 = lat2*RAD;
- double a = radLat1 - radLat2;
- double b = (lng1 - lng2)*RAD;
- double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a/2),2) +
- Math.cos(radLat1)*Math.cos(radLat2)*Math.pow(Math.sin(b/2),2)));
- s = s * EARTH_RADIUS;
- s = Math.round(s * 10000) / 10000;
- return s;
- }
-
- public static void main(String[] args){
- Double lat1 = 34.264648;
- Double lon1 = 108.952736;
-
- int radius = 1000;
- //[34.25566276027792,108.94186385411045,34.27363323972208,108.96360814588955]
- getAround(lat1,lon1,radius);
-
- //911717.0 34.264648,108.952736,39.904549,116.407288
- double dis = getDistance(108.952736,34.264648,116.407288,39.904549);
- System.out.println(dis);
- }
- }
复制代码 一共有两个方法
第一个是 根据提供的经度和纬度、以及半径,取得此半径内的最大最小经纬度
第二个就是根据提供的两个经纬度计算距离
from:http://go.cxweb.com.cn/bxq-x
|
|